S+(2(s+3))+(4s-5)=148

Solution for S+(2(s+3))+(4s-5)=148 equation:

Simplifying
S + (2(s + 3)) + (4s + -5) = 148

Reorder the terms:
S + (2(3 + s)) + (4s + -5) = 148
S + ((3 * 2 + s * 2)) + (4s + -5) = 148
S + ((6 + 2s)) + (4s + -5) = 148
S + (6 + 2s) + (4s + -5) = 148

Remove parenthesis around (6 + 2s)
S + 6 + 2s + (4s + -5) = 148

Reorder the terms:
S + 6 + 2s + (-5 + 4s) = 148

Remove parenthesis around (-5 + 4s)
S + 6 + 2s + -5 + 4s = 148

Reorder the terms:
6 + -5 + S + 2s + 4s = 148

Combine like terms: 6 + -5 = 1
1 + S + 2s + 4s = 148

Combine like terms: 2s + 4s = 6s
1 + S + 6s = 148

Solving
1 + S + 6s = 148

Solving for variable 'S'.

Move all terms containing S to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + S + -1 + 6s = 148 + -1

Reorder the terms:
1 + -1 + S + 6s = 148 + -1

Combine like terms: 1 + -1 = 0
0 + S + 6s = 148 + -1
S + 6s = 148 + -1

Combine like terms: 148 + -1 = 147
S + 6s = 147

Add '-6s' to each side of the equation.
S + 6s + -6s = 147 + -6s

Combine like terms: 6s + -6s = 0
S + 0 = 147 + -6s
S = 147 + -6s

Simplifying
S = 147 + -6s