If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=800-0.05R^2
We move all terms to the left:
-(800-0.05R^2)=0
We get rid of parentheses
0.05R^2-800=0
a = 0.05; b = 0; c = -800;
Δ = b2-4ac
Δ = 02-4·0.05·(-800)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*0.05}=\frac{0-4\sqrt{10}}{0.1} =-\frac{4\sqrt{10}}{0.1} =-\frac{\sqrt{10}}{0.025} $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*0.05}=\frac{0+4\sqrt{10}}{0.1} =\frac{4\sqrt{10}}{0.1} =\frac{\sqrt{10}}{0.025} $
| 0.2(x-8)=1.2 | | 3(3s+4)=66 | | -3+6b-7-4b=5(b+2)+1 | | |−3d|=15 | | R=90n-0.05n2 | | 4x-12+x+15=180 | | 5(2a+10)=110 | | 5(2a+10=110 | | 7b-15=5b=3 | | m/3=37 | | 1.9r+0.1=0.6 | | (2(r-3))/(4)-8=50 | | 120500/u=775 | | 5(2)+5y=-15 | | 5y+4=9y | | 5x-6+3x-44=180 | | 2^x+5=2^x+1 | | -17+n/5=-33 | | 5/6=x/112 | | 4x+70=2x+94 | | 5x+5(-3)=-15 | | 18-27x-29=7x+23 | | 20s^2+12s-5s-3=0 | | t-3/2+t+3/4=3-t/3+2 | | 4u=9u+u | | 4(v+8)=-8(v+5) | | -18=7y+9+10y | | 8x+10+-2x=4x-20 | | 1/2z+4=52z−8 | | 11v=6v+40 | | 17u=18+19u | | x3/8=1 |