R+3=90m2

Solution for R+3=90m2 equation:

+3=90R^2

We move all terms to the left:

+3-(90R^2)=0

a = -90; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-90)·3
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*-90}=\frac{0-6\sqrt{30}}{-180}
=-\frac{6\sqrt{30}}{-180}
=-\frac{\sqrt{30}}{-30}
$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*-90}=\frac{0+6\sqrt{30}}{-180}
=\frac{6\sqrt{30}}{-180}
=\frac{\sqrt{30}}{-30}
$