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(R)=R(60-3R)
We move all terms to the left:
(R)-(R(60-3R))=0
We add all the numbers together, and all the variables
R-(R(-3R+60))=0
We calculate terms in parentheses: -(R(-3R+60)), so:We get rid of parentheses
R(-3R+60)
We multiply parentheses
-3R^2+60R
Back to the equation:
-(-3R^2+60R)
3R^2-60R+R=0
We add all the numbers together, and all the variables
3R^2-59R=0
a = 3; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·3·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*3}=\frac{0}{6} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*3}=\frac{118}{6} =19+2/3 $
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