Q(x)=5x2+10x+7

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Solution for Q(x)=5x2+10x+7 equation: 



(Q)=5Q^2+10Q+7

We move all terms to the left:

(Q)-(5Q^2+10Q+7)=0

We get rid of parentheses

-5Q^2+Q-10Q-7=0

We add all the numbers together, and all the variables

-5Q^2-9Q-7=0

a = -5; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·(-5)·(-7)
Δ = -59
Delta is less than zero, so there is no solution for the equation

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