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=60P(P-3)
We move all terms to the left:
-(60P(P-3))=0
We calculate terms in parentheses: -(60P(P-3)), so:We get rid of parentheses
60P(P-3)
We multiply parentheses
60P^2-180P
Back to the equation:
-(60P^2-180P)
-60P^2+180P=0
a = -60; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-60)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-60}=\frac{-360}{-120} =+3 $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-60}=\frac{0}{-120} =0 $
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