P=5(2t-20

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Solution for P=5(2t-20 equation: 



=5(2P-20

We move all terms to the left:

-(5(2P-20)=0



We calculate terms in parentheses: -(5(2P-20), so:

5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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5(2P-20





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