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=3P-10/P
We move all terms to the left:
-(3P-10/P)=0
Domain of the equation: P)!=0We add all the numbers together, and all the variables
P!=0/1
P!=0
P∈R
-(+3P-10/P)=0
We get rid of parentheses
-3P+10/P=0
We multiply all the terms by the denominator
-3P*P+10=0
Wy multiply elements
-3P^2+10=0
a = -3; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-3)·10
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*-3}=\frac{0-2\sqrt{30}}{-6} =-\frac{2\sqrt{30}}{-6} =-\frac{\sqrt{30}}{-3} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*-3}=\frac{0+2\sqrt{30}}{-6} =\frac{2\sqrt{30}}{-6} =\frac{\sqrt{30}}{-3} $
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