P=2(3w-5)2w

Solution for P=2(3w-5)2w equation:

=2(3P-5)2P

We move all terms to the left:

-(2(3P-5)2P)=0


We calculate terms in parentheses: -(2(3P-5)2P), so:

2(3P-5)2P

We multiply parentheses

12P^2-20P

Back to the equation:

-(12P^2-20P)


We get rid of parentheses

-12P^2+20P=0

a = -12; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-12)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-12}=\frac{-40}{-24}
=1+2/3
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-12}=\frac{0}{-24}
=0
$