P=(b+c)/5

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Solution for P=(b+c)/5 equation: 


x in (-oo:+oo)

P = (b+c)/5 // - (b+c)/5

P-((b+c)/5) = 0

(-1*(b+c))/5+P = 0

(-1*(b+c))/5+(5*P)/5 = 0

5*P-1*(b+c) = 0

5*P-b-c = 0

(5*P-b-c)/5 = 0

(5*P-b-c)/5 = 0 // * 5

5*P-b-c = 0

x belongs to the empty set

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