P11(x)=5(x2+1)+16

Solution for P11(x)=5(x2+1)+16 equation:

11(P)=5(P2+1)+16

We move all terms to the left:

11(P)-(5(P2+1)+16)=0

We add all the numbers together, and all the variables

-(5(+P^2+1)+16)+11P=0


We calculate terms in parentheses: -(5(+P^2+1)+16), so:

5(+P^2+1)+16

We multiply parentheses

5P^2+5+16

We add all the numbers together, and all the variables

5P^2+21

Back to the equation:

-(5P^2+21)


We add all the numbers together, and all the variables

11P-(5P^2+21)=0

We get rid of parentheses

-5P^2+11P-21=0

a = -5; b = 11; c = -21;
Δ = b2-4ac
Δ = 112-4·(-5)·(-21)
Δ = -299
Delta is less than zero, so there is no solution for the equation