P+p2/3+p2/3=234

Solution for P+p2/3+p2/3=234 equation:

+P2/3+P2/3=234

We move all terms to the left:

+P2/3+P2/3-(234)=0

We multiply all the terms by the denominator


P2+P2-234*3=0

We add all the numbers together, and all the variables

2P^2-702=0

a = 2; b = 0; c = -702;
Δ = b2-4ac
Δ = 02-4·2·(-702)
Δ = 5616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5616}=\sqrt{144*39}=\sqrt{144}*\sqrt{39}=12\sqrt{39}$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{39}}{2*2}=\frac{0-12\sqrt{39}}{4}
=-\frac{12\sqrt{39}}{4}
=-3\sqrt{39}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{39}}{2*2}=\frac{0+12\sqrt{39}}{4}
=\frac{12\sqrt{39}}{4}
=3\sqrt{39}
$