P(x)=(2x+5)(x+1)

Solution for P(x)=(2x+5)(x+1) equation:

(P)=(2P+5)(P+1)

We move all terms to the left:

(P)-((2P+5)(P+1))=0

We multiply parentheses ..

-((+2P^2+2P+5P+5))+P=0


We calculate terms in parentheses: -((+2P^2+2P+5P+5)), so:

(+2P^2+2P+5P+5)

We get rid of parentheses

2P^2+2P+5P+5

We add all the numbers together, and all the variables

2P^2+7P+5

Back to the equation:

-(2P^2+7P+5)


We add all the numbers together, and all the variables

P-(2P^2+7P+5)=0

We get rid of parentheses

-2P^2+P-7P-5=0

We add all the numbers together, and all the variables

-2P^2-6P-5=0

a = -2; b = -6; c = -5;
Δ = b2-4ac
Δ = -62-4·(-2)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation