P(x)+Q(x)=(3x+1)+(2x-4)

Solution for P(x)+Q(x)=(3x+1)+(2x-4) equation:

(P)+(P)=(3P+1)+(2P-4)

We move all terms to the left:

(P)+(P)-((3P+1)+(2P-4))=0

We add all the numbers together, and all the variables

2P-((3P+1)+(2P-4))=0


We calculate terms in parentheses: -((3P+1)+(2P-4)), so:

(3P+1)+(2P-4)

We get rid of parentheses

3P+2P+1-4

We add all the numbers together, and all the variables

5P-3

Back to the equation:

-(5P-3)


We get rid of parentheses

2P-5P+3=0

We add all the numbers together, and all the variables

-3P+3=0

We move all terms containing P to the left, all other terms to the right

-3P=-3

P=-3/-3

P=1