N=100-4(3+m)

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Solution for N=100-4(3+m) equation: 



=100-4(3+N)

We move all terms to the left:

-(100-4(3+N))=0

We add all the numbers together, and all the variables

-(100-4(N+3))=0



We calculate terms in parentheses: -(100-4(N+3)), so:

100-4(N+3)

determiningTheFunctionDomain
-4(N+3)+100

We multiply parentheses

-4N-12+100

We add all the numbers together, and all the variables

-4N+88

Back to the equation:

-(-4N+88)



We get rid of parentheses

4N-88=0

We move all terms containing N to the left, all other terms to the right

4N=88

N=88/4

N=22

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