N=(p-k)/j

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Solution for N=(p-k)/j equation: 


x in (-oo:+oo)

N = (p-k)/j // - (p-k)/j

N-((p-k)/j) = 0

(-1*(p-k))/j+N = 0

(-1*(p-k))/j+(N*j)/j = 0

N*j-1*(p-k) = 0

N*j+k-p = 0

(N*j+k-p)/j = 0

(N*j+k-p)/j = 0 // * j

N*j+k-p = 0

x belongs to the empty set

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