N=(2/3)(4+m)

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Solution for N=(2/3)(4+m) equation: 


x in (-oo:+oo)

N = (2/3)*(m+4) // - (2/3)*(m+4)

N-((2/3)*(m+4)) = 0

(-2/3)*(m+4)+N = 0

N-2/3*(m+4) = 0

N-2/3*(m+4) = 0

N-2/3*m-8/3 = 0

N-2/3*m-8/3 = 0

x belongs to the empty set

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