N+5n+7=3n-2+2(2n+1)

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Solution for N+5n+7=3n-2+2(2n+1) equation: 



+5N+7=3N-2+2(2N+1)

We move all terms to the left:

+5N+7-(3N-2+2(2N+1))=0



We calculate terms in parentheses: -(3N-2+2(2N+1)), so:

3N-2+2(2N+1)

determiningTheFunctionDomain
3N+2(2N+1)-2

We multiply parentheses

3N+4N+2-2

We add all the numbers together, and all the variables

7N

Back to the equation:

-(7N)



We add all the numbers together, and all the variables

-2N+7=0

We move all terms containing N to the left, all other terms to the right

-2N=-7

N=-7/-2

N=3+1/2

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