N+3(n-4)=16

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Solution for N+3(n-4)=16 equation: 



+3(N-4)=16

We move all terms to the left:

+3(N-4)-(16)=0

We multiply parentheses

3N-12-16=0

We add all the numbers together, and all the variables

3N-28=0

We move all terms containing N to the left, all other terms to the right

3N=28

N=28/3

N=9+1/3

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