N+3(4+n)=8n-2(7+n)

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Solution for N+3(4+n)=8n-2(7+n) equation: 



+3(4+N)=8N-2(7+N)

We move all terms to the left:

+3(4+N)-(8N-2(7+N))=0

We add all the numbers together, and all the variables

3(N+4)-(8N-2(N+7))=0

We multiply parentheses

3N-(8N-2(N+7))+12=0



We calculate terms in parentheses: -(8N-2(N+7)), so:

8N-2(N+7)

We multiply parentheses

8N-2N-14

We add all the numbers together, and all the variables

6N-14

Back to the equation:

-(6N-14)



We get rid of parentheses

3N-6N+14+12=0

We add all the numbers together, and all the variables

-3N+26=0

We move all terms containing N to the left, all other terms to the right

-3N=-26

N=-26/-3

N=8+2/3

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