M+5/8m+3/5m=801

Solution for M+5/8m+3/5m=801 equation:

+5/8M+3/5M=801

We move all terms to the left:

+5/8M+3/5M-(801)=0


Domain of the equation: 8M!=0

M!=0/8

M!=0

M∈R



Domain of the equation: 5M!=0

M!=0/5

M!=0

M∈R


We calculate fractions


25M/40M^2+24M/40M^2-801=0

We multiply all the terms by the denominator


25M+24M-801*40M^2=0

We add all the numbers together, and all the variables

49M-801*40M^2=0

Wy multiply elements

-32040M^2+49M=0

a = -32040; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-32040)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-32040}=\frac{-98}{-64080}
=49/32040
$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-32040}=\frac{0}{-64080}
=0
$