Log(x+1)-log(2x-3)=2

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Solution for Log(x+1)-log(2x-3)=2 equation: 


Simplifying
Log(x + 1) + -1log(2x + -3) = 2

Reorder the terms:
goL(1 + x) + -1log(2x + -3) = 2
(1 * goL + x * goL) + -1log(2x + -3) = 2
(1goL + goxL) + -1log(2x + -3) = 2

Reorder the terms:
1goL + goxL + -1glo(-3 + 2x) = 2
1goL + goxL + (-3 * -1glo + 2x * -1glo) = 2
1goL + goxL + (3glo + -2glox) = 2

Reorder the terms:
3glo + -2glox + 1goL + goxL = 2

Solving
3glo + -2glox + 1goL + goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 3glo + -2glox + 1goL + goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 3glo + -2glox + 1goL + goxL = 0

The solution to this equation could not be determined.

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