Log(7x+1)=(x-2)+1

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Solution for Log(7x+1)=(x-2)+1 equation:


Simplifying
Log(7x + 1) = (x + -2) + 1

Reorder the terms:
goL(1 + 7x) = (x + -2) + 1
(1 * goL + 7x * goL) = (x + -2) + 1
(1goL + 7goxL) = (x + -2) + 1

Reorder the terms:
1goL + 7goxL = (-2 + x) + 1

Remove parenthesis around (-2 + x)
1goL + 7goxL = -2 + x + 1

Reorder the terms:
1goL + 7goxL = -2 + 1 + x

Combine like terms: -2 + 1 = -1
1goL + 7goxL = -1 + x

Solving
1goL + 7goxL = -1 + x

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
1 + 1goL + 7goxL + -1x = -1 + x + 1 + -1x

Reorder the terms:
1 + 1goL + 7goxL + -1x = -1 + 1 + x + -1x

Combine like terms: -1 + 1 = 0
1 + 1goL + 7goxL + -1x = 0 + x + -1x
1 + 1goL + 7goxL + -1x = x + -1x

Combine like terms: x + -1x = 0
1 + 1goL + 7goxL + -1x = 0

The solution to this equation could not be determined.

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