Log(3x-1)+log(x-1)=6

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Solution for Log(3x-1)+log(x-1)=6 equation: 


Simplifying
Log(3x + -1) + log(x + -1) = 6

Reorder the terms:
goL(-1 + 3x) + log(x + -1) = 6
(-1 * goL + 3x * goL) + log(x + -1) = 6
(-1goL + 3goxL) + log(x + -1) = 6

Reorder the terms:
-1goL + 3goxL + glo(-1 + x) = 6
-1goL + 3goxL + (-1 * glo + x * glo) = 6
-1goL + 3goxL + (-1glo + glox) = 6

Reorder the terms:
-1glo + glox + -1goL + 3goxL = 6

Solving
-1glo + glox + -1goL + 3goxL = 6

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-6 + -1glo + glox + -1goL + 3goxL = 6 + -6

Combine like terms: 6 + -6 = 0
-6 + -1glo + glox + -1goL + 3goxL = 0

The solution to this equation could not be determined.

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