Log(3x+2)=1+log(2x)

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Solution for Log(3x+2)=1+log(2x) equation: 


Simplifying
Log(3x + 2) = 1 + log(2x)

Reorder the terms:
goL(2 + 3x) = 1 + log(2x)
(2 * goL + 3x * goL) = 1 + log(2x)
(2goL + 3goxL) = 1 + log(2x)

Remove parenthesis around (2x)
2goL + 3goxL = 1 + glo * 2x

Reorder the terms for easier multiplication:
2goL + 3goxL = 1 + 2glo * x

Multiply glo * x
2goL + 3goxL = 1 + 2glox

Solving
2goL + 3goxL = 1 + 2glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-2glox' to each side of the equation.
2goL + -2glox + 3goxL = 1 + 2glox + -2glox

Reorder the terms:
-2glox + 2goL + 3goxL = 1 + 2glox + -2glox

Combine like terms: 2glox + -2glox = 0
-2glox + 2goL + 3goxL = 1 + 0
-2glox + 2goL + 3goxL = 1

Reorder the terms:
-1 + -2glox + 2goL + 3goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -2glox + 2goL + 3goxL = 0

The solution to this equation could not be determined.

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