Log(3x+1)-log(4)=2

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Solution for Log(3x+1)-log(4)=2 equation:


Simplifying
Log(3x + 1) + -1log(4) = 2

Reorder the terms:
goL(1 + 3x) + -1log(4) = 2
(1 * goL + 3x * goL) + -1log(4) = 2
(1goL + 3goxL) + -1log(4) = 2

Reorder the terms for easier multiplication:
1goL + 3goxL + -1 * 4glo = 2

Multiply -1 * 4
1goL + 3goxL + -4glo = 2

Reorder the terms:
-4glo + 1goL + 3goxL = 2

Solving
-4glo + 1goL + 3goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -4glo + 1goL + 3goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -4glo + 1goL + 3goxL = 0

The solution to this equation could not be determined.

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