Log(2x+4)-log(x+-1)=1

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Solution for Log(2x+4)-log(x+-1)=1 equation: 


Simplifying
Log(2x + 4) + -1log(x + -1) = 1

Reorder the terms:
goL(4 + 2x) + -1log(x + -1) = 1
(4 * goL + 2x * goL) + -1log(x + -1) = 1
(4goL + 2goxL) + -1log(x + -1) = 1

Reorder the terms:
4goL + 2goxL + -1glo(-1 + x) = 1
4goL + 2goxL + (-1 * -1glo + x * -1glo) = 1
4goL + 2goxL + (1glo + -1glox) = 1

Reorder the terms:
1glo + -1glox + 4goL + 2goxL = 1

Solving
1glo + -1glox + 4goL + 2goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 1glo + -1glox + 4goL + 2goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1glo + -1glox + 4goL + 2goxL = 0

The solution to this equation could not be determined.

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