Log(2x+1)-log(3x)=12

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Solution for Log(2x+1)-log(3x)=12 equation:


Simplifying
Log(2x + 1) + -1log(3x) = 12

Reorder the terms:
goL(1 + 2x) + -1log(3x) = 12
(1 * goL + 2x * goL) + -1log(3x) = 12
(1goL + 2goxL) + -1log(3x) = 12

Remove parenthesis around (3x)
1goL + 2goxL + -1glo * 3x = 12

Reorder the terms for easier multiplication:
1goL + 2goxL + -1 * 3glo * x = 12

Multiply -1 * 3
1goL + 2goxL + -3glo * x = 12

Multiply glo * x
1goL + 2goxL + -3glox = 12

Reorder the terms:
-3glox + 1goL + 2goxL = 12

Solving
-3glox + 1goL + 2goxL = 12

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-12 + -3glox + 1goL + 2goxL = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + -3glox + 1goL + 2goxL = 0

The solution to this equation could not be determined.

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