Log(2x+1)+log(x-2)-2=0

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Solution for Log(2x+1)+log(x-2)-2=0 equation: 


Simplifying
Log(2x + 1) + log(x + -2) + -2 = 0

Reorder the terms:
goL(1 + 2x) + log(x + -2) + -2 = 0
(1 * goL + 2x * goL) + log(x + -2) + -2 = 0
(1goL + 2goxL) + log(x + -2) + -2 = 0

Reorder the terms:
1goL + 2goxL + glo(-2 + x) + -2 = 0
1goL + 2goxL + (-2 * glo + x * glo) + -2 = 0
1goL + 2goxL + (-2glo + glox) + -2 = 0

Reorder the terms:
-2 + -2glo + glox + 1goL + 2goxL = 0

Solving
-2 + -2glo + glox + 1goL + 2goxL = 0

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + -2glo + glox + 1goL + 2 + 2goxL = 0 + 2

Reorder the terms:
-2 + 2 + -2glo + glox + 1goL + 2goxL = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -2glo + glox + 1goL + 2goxL = 0 + 2
-2glo + glox + 1goL + 2goxL = 0 + 2

Combine like terms: 0 + 2 = 2
-2glo + glox + 1goL + 2goxL = 2

Reorder the terms:
-2 + -2glo + glox + 1goL + 2goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -2glo + glox + 1goL + 2goxL = 0

The solution to this equation could not be determined.

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