Log(2x+1)+log(x+4)=1

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Solution for Log(2x+1)+log(x+4)=1 equation: 


Simplifying
Log(2x + 1) + log(x + 4) = 1

Reorder the terms:
goL(1 + 2x) + log(x + 4) = 1
(1 * goL + 2x * goL) + log(x + 4) = 1
(1goL + 2goxL) + log(x + 4) = 1

Reorder the terms:
1goL + 2goxL + glo(4 + x) = 1
1goL + 2goxL + (4 * glo + x * glo) = 1
1goL + 2goxL + (4glo + glox) = 1

Reorder the terms:
4glo + glox + 1goL + 2goxL = 1

Solving
4glo + glox + 1goL + 2goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 4glo + glox + 1goL + 2goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 4glo + glox + 1goL + 2goxL = 0

The solution to this equation could not be determined.

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