Log(2x)+log(x-1)=1

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Solution for Log(2x)+log(x-1)=1 equation: 


Simplifying
Log(2x) + log(x + -1) = 1

Remove parenthesis around (2x)
goL * 2x + log(x + -1) = 1

Reorder the terms for easier multiplication:
2goL * x + log(x + -1) = 1

Multiply goL * x
2goxL + log(x + -1) = 1

Reorder the terms:
2goxL + glo(-1 + x) = 1
2goxL + (-1 * glo + x * glo) = 1
2goxL + (-1glo + glox) = 1

Reorder the terms:
-1glo + glox + 2goxL = 1

Solving
-1glo + glox + 2goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -1glo + glox + 2goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1glo + glox + 2goxL = 0

The solution to this equation could not be determined.

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