Log(14x)-log(x+2)=1

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Solution for Log(14x)-log(x+2)=1 equation: 


Simplifying
Log(14x) + -1log(x + 2) = 1

Remove parenthesis around (14x)
goL * 14x + -1log(x + 2) = 1

Reorder the terms for easier multiplication:
14goL * x + -1log(x + 2) = 1

Multiply goL * x
14goxL + -1log(x + 2) = 1

Reorder the terms:
14goxL + -1glo(2 + x) = 1
14goxL + (2 * -1glo + x * -1glo) = 1
14goxL + (-2glo + -1glox) = 1

Reorder the terms:
-2glo + -1glox + 14goxL = 1

Solving
-2glo + -1glox + 14goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -2glo + -1glox + 14goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -2glo + -1glox + 14goxL = 0

The solution to this equation could not be determined.

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