Log(1-X)-log(1+x)=2

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Solution for Log(1-X)-log(1+x)=2 equation: 


Simplifying
Log(1 + -1X) + -1log(1 + x) = 2
(1 * goL + -1X * goL) + -1log(1 + x) = 2
(1goL + -1goLX) + -1log(1 + x) = 2
1goL + -1goLX + (1 * -1glo + x * -1glo) = 2
1goL + -1goLX + (-1glo + -1glox) = 2

Reorder the terms:
-1glo + -1glox + 1goL + -1goLX = 2

Solving
-1glo + -1glox + 1goL + -1goLX = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -1glo + -1glox + 1goL + -1goLX = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -1glo + -1glox + 1goL + -1goLX = 0

The solution to this equation could not be determined.

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