Ln(lny)=lnx+c

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Solution for Ln(lny)=lnx+c equation: 


Simplifying
Ln(lny) = lnx + c

Multiply nL * lny
ln2yL = lnx + c

Reorder the terms:
ln2yL = c + lnx

Solving
ln2yL = c + lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1lnx' to each side of the equation.
-1lnx + ln2yL = c + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
-1lnx + ln2yL = c + 0
-1lnx + ln2yL = c

Reorder the terms:
-1c + -1lnx + ln2yL = c + -1c

Combine like terms: c + -1c = 0
-1c + -1lnx + ln2yL = 0

The solution to this equation could not be determined.

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