Ln(3x-5)-ln(x)=1

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Solution for Ln(3x-5)-ln(x)=1 equation: 


Simplifying
Ln(3x + -5) + -1ln(x) = 1

Reorder the terms:
nL(-5 + 3x) + -1ln(x) = 1
(-5 * nL + 3x * nL) + -1ln(x) = 1
(-5nL + 3nxL) + -1ln(x) = 1

Multiply ln * x
-5nL + 3nxL + -1lnx = 1

Reorder the terms:
-1lnx + -5nL + 3nxL = 1

Solving
-1lnx + -5nL + 3nxL = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '5nL' to each side of the equation.
-1lnx + -5nL + 5nL + 3nxL = 1 + 5nL

Combine like terms: -5nL + 5nL = 0
-1lnx + 0 + 3nxL = 1 + 5nL
-1lnx + 3nxL = 1 + 5nL

Add '-3nxL' to each side of the equation.
-1lnx + 3nxL + -3nxL = 1 + 5nL + -3nxL

Combine like terms: 3nxL + -3nxL = 0
-1lnx + 0 = 1 + 5nL + -3nxL
-1lnx = 1 + 5nL + -3nxL

Divide each side by '-1nx'.
l = -1n-1x-1 + -5x-1L + 3L

Simplifying
l = -1n-1x-1 + -5x-1L + 3L

Reorder the terms:
l = 3L + -1n-1x-1 + -5x-1L

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