Ln(2x+1)-ln(x)=5

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Solution for Ln(2x+1)-ln(x)=5 equation: 


Simplifying
Ln(2x + 1) + -1ln(x) = 5

Reorder the terms:
nL(1 + 2x) + -1ln(x) = 5
(1 * nL + 2x * nL) + -1ln(x) = 5
(1nL + 2nxL) + -1ln(x) = 5

Multiply ln * x
1nL + 2nxL + -1lnx = 5

Reorder the terms:
-1lnx + 1nL + 2nxL = 5

Solving
-1lnx + 1nL + 2nxL = 5

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1nL' to each side of the equation.
-1lnx + 1nL + -1nL + 2nxL = 5 + -1nL

Combine like terms: 1nL + -1nL = 0
-1lnx + 0 + 2nxL = 5 + -1nL
-1lnx + 2nxL = 5 + -1nL

Add '-2nxL' to each side of the equation.
-1lnx + 2nxL + -2nxL = 5 + -1nL + -2nxL

Combine like terms: 2nxL + -2nxL = 0
-1lnx + 0 = 5 + -1nL + -2nxL
-1lnx = 5 + -1nL + -2nxL

Divide each side by '-1nx'.
l = -5n-1x-1 + x-1L + 2L

Simplifying
l = -5n-1x-1 + x-1L + 2L

Reorder the terms:
l = 2L + -5n-1x-1 + x-1L

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