Ln(2x+1)+ln(X)=5

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Solution for Ln(2x+1)+ln(X)=5 equation: 


Simplifying
Ln(2x + 1) + ln(X) = 5

Reorder the terms:
nL(1 + 2x) + ln(X) = 5
(1 * nL + 2x * nL) + ln(X) = 5
(1nL + 2nxL) + ln(X) = 5

Multiply ln * X
1nL + 2nxL + lnX = 5

Reorder the terms:
lnX + 1nL + 2nxL = 5

Solving
lnX + 1nL + 2nxL = 5

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1nL' to each side of the equation.
lnX + 1nL + -1nL + 2nxL = 5 + -1nL

Combine like terms: 1nL + -1nL = 0
lnX + 0 + 2nxL = 5 + -1nL
lnX + 2nxL = 5 + -1nL

Add '-2nxL' to each side of the equation.
lnX + 2nxL + -2nxL = 5 + -1nL + -2nxL

Combine like terms: 2nxL + -2nxL = 0
lnX + 0 = 5 + -1nL + -2nxL
lnX = 5 + -1nL + -2nxL

Divide each side by 'nX'.
l = 5n-1X-1 + -1LX-1 + -2xLX-1

Simplifying
l = 5n-1X-1 + -1LX-1 + -2xLX-1

Reorder the terms:
l = -1LX-1 + 5n-1X-1 + -2xLX-1

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