K(3n+12)=n+4

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Solution for K(3n+12)=n+4 equation: 



(3K+12)=K+4

We move all terms to the left:

(3K+12)-(K+4)=0

We get rid of parentheses

3K-K+12-4=0

We add all the numbers together, and all the variables

2K+8=0

We move all terms containing K to the left, all other terms to the right

2K=-8

K=-8/2

K=-4

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