J-2(1-2j)=(j-3)+5

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Solution for J-2(1-2j)=(j-3)+5 equation:


Simplifying
J + -2(1 + -2j) = (j + -3) + 5
J + (1 * -2 + -2j * -2) = (j + -3) + 5
J + (-2 + 4j) = (j + -3) + 5

Reorder the terms:
-2 + J + 4j = (j + -3) + 5

Reorder the terms:
-2 + J + 4j = (-3 + j) + 5

Remove parenthesis around (-3 + j)
-2 + J + 4j = -3 + j + 5

Reorder the terms:
-2 + J + 4j = -3 + 5 + j

Combine like terms: -3 + 5 = 2
-2 + J + 4j = 2 + j

Solving
-2 + J + 4j = 2 + j

Solving for variable 'J'.

Move all terms containing J to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + J + 2 + 4j = 2 + 2 + j

Reorder the terms:
-2 + 2 + J + 4j = 2 + 2 + j

Combine like terms: -2 + 2 = 0
0 + J + 4j = 2 + 2 + j
J + 4j = 2 + 2 + j

Combine like terms: 2 + 2 = 4
J + 4j = 4 + j

Add '-4j' to each side of the equation.
J + 4j + -4j = 4 + j + -4j

Combine like terms: 4j + -4j = 0
J + 0 = 4 + j + -4j
J = 4 + j + -4j

Combine like terms: j + -4j = -3j
J = 4 + -3j

Simplifying
J = 4 + -3j

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