J-(4+j)=5(3j-1)

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Solution for J-(4+j)=5(3j-1) equation: 



-(4+J)=5(3J-1)

We move all terms to the left:

-(4+J)-(5(3J-1))=0

We add all the numbers together, and all the variables

-(J+4)-(5(3J-1))=0

We get rid of parentheses

-J-(5(3J-1))-4=0



We calculate terms in parentheses: -(5(3J-1)), so:

5(3J-1)

We multiply parentheses

15J-5

Back to the equation:

-(15J-5)



We add all the numbers together, and all the variables

-1J-(15J-5)-4=0

We get rid of parentheses

-1J-15J+5-4=0

We add all the numbers together, and all the variables

-16J+1=0

We move all terms containing J to the left, all other terms to the right

-16J=-1

J=-1/-16

J=1/16

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