J(12)=3/4x+5

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Solution for J(12)=3/4x+5 equation: 



(12)=3/4J+5

We move all terms to the left:

(12)-(3/4J+5)=0



Domain of the equation: 4J+5)!=0

J∈R



We get rid of parentheses

-3/4J-5+12=0

We multiply all the terms by the denominator


-5*4J+12*4J-3=0

Wy multiply elements

-20J+48J-3=0

We add all the numbers together, and all the variables

28J-3=0

We move all terms containing J to the left, all other terms to the right

28J=3

J=3/28

J=3/28

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