In(x)+(x+1)=2

Solution for In(x)+(x+1)=2 equation:

Simplifying
In(x) + (x + 1) = 2

Multiply nI * x
nxI + (x + 1) = 2

Reorder the terms:
nxI + (1 + x) = 2

Remove parenthesis around (1 + x)
nxI + 1 + x = 2

Reorder the terms:
1 + nxI + x = 2

Solving
1 + nxI + x = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + nxI + -1 + x = 2 + -1

Reorder the terms:
1 + -1 + nxI + x = 2 + -1

Combine like terms: 1 + -1 = 0
0 + nxI + x = 2 + -1
nxI + x = 2 + -1

Combine like terms: 2 + -1 = 1
nxI + x = 1

Add '-1x' to each side of the equation.
nxI + x + -1x = 1 + -1x

Combine like terms: x + -1x = 0
nxI + 0 = 1 + -1x
nxI = 1 + -1x

Divide each side by 'xI'.
n = x-1I-1 + -1I-1

Simplifying
n = x-1I-1 + -1I-1

Reorder the terms:
n = -1I-1 + x-1I-1