In(1-y)(1+y)=-2(cosx)

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Solution for In(1-y)(1+y)=-2(cosx) equation: 


Simplifying
In(1 + -1y)(1 + y) = -2(cosx)

Multiply (1 + -1y) * (1 + y)
nI(1(1 + y) + -1y * (1 + y)) = -2(cosx)
nI((1 * 1 + y * 1) + -1y * (1 + y)) = -2(cosx)
nI((1 + 1y) + -1y * (1 + y)) = -2(cosx)
nI(1 + 1y + (1 * -1y + y * -1y)) = -2(cosx)
nI(1 + 1y + (-1y + -1y2)) = -2(cosx)

Combine like terms: 1y + -1y = 0
nI(1 + 0 + -1y2) = -2(cosx)
nI(1 + -1y2) = -2(cosx)
(1 * nI + -1y2 * nI) = -2(cosx)
(1nI + -1ny2I) = -2(cosx)

Solving
1nI + -1ny2I = -2cosx

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Reorder the terms:
2cosx + 1nI + -1ny2I = -2cosx + 2cosx

Combine like terms: -2cosx + 2cosx = 0
2cosx + 1nI + -1ny2I = 0

The solution to this equation could not be determined.

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