I59-(2x+4)=4(x+5)+x

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Solution for I59-(2x+4)=4(x+5)+x equation: 



59-(2I+4)=4(I+5)+I

We move all terms to the left:

59-(2I+4)-(4(I+5)+I)=0

We get rid of parentheses

-2I-(4(I+5)+I)-4+59=0



We calculate terms in parentheses: -(4(I+5)+I), so:

4(I+5)+I

We add all the numbers together, and all the variables

I+4(I+5)

We multiply parentheses

I+4I+20

We add all the numbers together, and all the variables

5I+20

Back to the equation:

-(5I+20)



We add all the numbers together, and all the variables

-2I-(5I+20)+55=0

We get rid of parentheses

-2I-5I-20+55=0

We add all the numbers together, and all the variables

-7I+35=0

We move all terms containing I to the left, all other terms to the right

-7I=-35

I=-35/-7

I=+5

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