I4(y+2)+1.3=3(y+2.1)

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Solution for I4(y+2)+1.3=3(y+2.1) equation: 



4(I+2)+1.3=3(I+2.1)

We move all terms to the left:

4(I+2)+1.3-(3(I+2.1))=0

We multiply parentheses

4I-(3(I+2.1))+8+1.3=0



We calculate terms in parentheses: -(3(I+2.1)), so:

3(I+2.1)

We multiply parentheses

3I+6.3

Back to the equation:

-(3I+6.3)



We add all the numbers together, and all the variables

4I-(3I+6.3)+9.3=0

We get rid of parentheses

4I-3I-6.3+9.3=0

We add all the numbers together, and all the variables

I+3=0

We move all terms containing I to the left, all other terms to the right

I=-3

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