I3x-5I+I4x+3I=12

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Solution for I3x-5I+I4x+3I=12 equation: 



3I-5+4I+3=12

We move all terms to the left:

3I-5+4I+3-(12)=0

We add all the numbers together, and all the variables

7I-14=0

We move all terms containing I to the left, all other terms to the right

7I=14

I=14/7

I=2

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