I3(6x+8)=4(3x+9)

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Solution for I3(6x+8)=4(3x+9) equation: 



3(6I+8)=4(3I+9)

We move all terms to the left:

3(6I+8)-(4(3I+9))=0

We multiply parentheses

18I-(4(3I+9))+24=0



We calculate terms in parentheses: -(4(3I+9)), so:

4(3I+9)

We multiply parentheses

12I+36

Back to the equation:

-(12I+36)



We get rid of parentheses

18I-12I-36+24=0

We add all the numbers together, and all the variables

6I-12=0

We move all terms containing I to the left, all other terms to the right

6I=12

I=12/6

I=2

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