I3(4x-1)=30+13x

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Solution for I3(4x-1)=30+13x equation: 



3(4I-1)=30+13I

We move all terms to the left:

3(4I-1)-(30+13I)=0

We add all the numbers together, and all the variables

3(4I-1)-(13I+30)=0

We multiply parentheses

12I-(13I+30)-3=0

We get rid of parentheses

12I-13I-30-3=0

We add all the numbers together, and all the variables

-1I-33=0

We move all terms containing I to the left, all other terms to the right

-I=33

I=33/-1

I=-33

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