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/I-I/6=2/3
We move all terms to the left:
/I-I/6-(2/3)=0
Domain of the equation: I!=0We add all the numbers together, and all the variables
I∈R
/I-I/6-(+2/3)=0
We get rid of parentheses
/I-I/6-2/3=0
We calculate fractions
(-9I^2)/54I+()/54I+(-72I)/54I=0
We multiply all the terms by the denominator
(-9I^2)+(-72I)+()=0
We add all the numbers together, and all the variables
(-9I^2)+(-72I)=0
We get rid of parentheses
-9I^2-72I=0
a = -9; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·(-9)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*-9}=\frac{0}{-18} =0 $$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*-9}=\frac{144}{-18} =-8 $
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