I/4(-8n+68)=-2(2n-4)

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Solution for I/4(-8n+68)=-2(2n-4) equation: 



/4(-8I+68)=-2(2I-4)

We move all terms to the left:

/4(-8I+68)-(-2(2I-4))=0



Domain of the equation: 4(-8I+68)!=0

I∈R



We multiply all the terms by the denominator


-((-2(2I-4)))*4(-8I+68)+=0



We calculate terms in parentheses: -((-2(2I-4)))*4(-8I+68), so:

(-2(2I-4)))*4(-8I+68

We add all the numbers together, and all the variables

-8I+(-2(2I-4)))*4(+68

Back to the equation:

-(-8I+(-2(2I-4)))*4(+68)



We add all the numbers together, and all the variables

-(-8I+(-2(2I-4)))*468+=0

We add all the numbers together, and all the variables

-(-8I+(-2(2I-4)))*468=0

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